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Question

A radioactive element X has an atomic number of 100. It decays directly into an element Y which decays directly into an element Z. In both processes a charged particle is emitted. Which of the following statement would be true?

A
Y has an atomic number of 102
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B
Z has an atomic number of 101
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C
Z has an atomic number of 97
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D
Z has an atomic number of 99
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Solution

The correct option is C Z has an atomic number of 99
Two charged particles decay means one alpha and one beta particles decay and by these two particles decay, proton no. of nuclei decay by one unit and daughter nuclei have atomic no. of 99.
(X and Y can decay one α each or one β each or X-decays, 1α, Y-decay 1β or X-decays 1β and Y-decays 1α.)

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