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Question

A radioactive element X has an atomic number of 100. It decays directly into an element Y which decays directly into the element Z. In both processes a charged particle is emitted. Which of the following statements would be true?

A
Y has an atomic number of 102
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B
Y has an atomic number of 101
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C
Z has an atomic number of 100
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D
Z has an atomic number of 99
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Solution

The correct options are
A Y has an atomic number of 101
C Z has an atomic number of 99

Firstly X looses a β paticle and form Y which has an atomic number of 101.
Then it looses a α particle and form Z of atomic number 99


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