A radioactive isotope disintegrates and emits $6 β$ and $7 α$ particles to forma a stable product. Find the difference between atomic number of parent radioactive isotope and the stable product.

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Solution

The difference between atomic number of parent radioactive isotope and the stable product is $7 \times 2 - 6$ = $8$

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Similar questions

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(IIT-JEE, 2004)

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A radioactive isotope disintegrates and emits 6β and 7α particles to forma a stable product. Find the difference between atomic number of parent radioactive isotope and the stable product.

The difference between atomic number of parent radioactive isotope and the stable product is 7×2−6 = 8

A radioactive isotope disintegrates and emits $6 β$ and $7 α$ particles to forma a stable product. Find the difference between atomic number of parent radioactive isotope and the stable product.

The difference between atomic number of parent radioactive isotope and the stable product is $7 \times 2 - 6$ = $8$