A radioactive material decrease by simultaneous emissions of two particles with half life 1620 years and 810 years the time after which 1/4 th of the material remained is

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Solution

When a body emits two different types of particles with different half times net half life is given by

1/t = 1/t1 + 1/t2
here t1 = 1620 yrs
And t2 = 810 yes
Solving we get t = 540 years

For activity to reduced to 1/4 th 2 half lives are required so time after which 1/4th will remain = 2 x 540 = 1080 years

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