A radioactive nucleus can decay by two different processes. The mean value period for the first process is t1 and that for the second process is t2. The effective mean value period for the two processes is
A
t1+t22
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B
t1+t2
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C
√t1t2
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D
t1t2t1+t2
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Solution
The correct option is Bt1t2t1+t2 Mean value: λ1=1t1 λ2=1t2
First order decay: dNdt=−(λ1N+λ2N) dNdt=−(λ1+λ2) dNdt=−(1t1+1t2)N dNdt=−(t1+t2t1t2)N dNdt=−λeffN teq=1λeff