A radioactive nucleus has specific binding energy - E1- It emits an -particle- The resulting nucleus has specific binding energy - E2- Then

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Nuclear Force

A radioactive...

Question

A radioactive nucleus has specific binding energy ' $E_{1}$ '. It emits an $α$ -particle. The resulting nucleus has specific binding energy ' $E_{2}$ '. Then

E_{2} = E_{1}

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E_{2} < E_{1}

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E_{2} > E_{1}

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E_{2} = 0

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Solution

The correct option is C $E_{2} > E_{1}$
A radioactive nucleus always decays into more stable nucleus and high binding energy corresponds to more stable nucleus. Therefore, after emitting an alpha particle energy $E_{2}$ will be more than the initial energy $E_{1}$ .

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A radioactive nucleus has specific binding energy 'E1'. It emits an α-particle. The resulting nucleus has specific binding energy 'E2'. Then

The correct option is C E2>E1A radioactive nucleus always decays into more stable nucleus and high binding energy corresponds to more stable nucleus. Therefore, after emitting an alpha particle energy E2 will be more than the initial energy E1.

A radioactive nucleus has specific binding energy ' $E_{1}$ '. It emits an $α$ -particle. The resulting nucleus has specific binding energy ' $E_{2}$ '. Then

The correct option is C $E_{2} > E_{1}$
A radioactive nucleus always decays into more stable nucleus and high binding energy corresponds to more stable nucleus. Therefore, after emitting an alpha particle energy $E_{2}$ will be more than the initial energy $E_{1}$ .