A radioactive nucleus undergoes a series of decay according to the scheme- A a - A 1 - A 2 - A 3 - A 4If the mass number and atomic number of -A- are 180 and 72 respectively- then the mass number and atomic number for A 4-

The correct option is B 172 and 69As we know, mass and charge of #160; #160; #160; #160; #160; #160; #160; #160; #160; α = 4 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Alpha Decay

A radioactive...

Question

A radioactive nucleus undergoes a series of decay according to the scheme:
$A a ⟶ A_{1} β ⟶ A_{2} {α ⟶ A}_{3} {γ ⟶ A}_{4}$

If the mass number and atomic number of `A' are 180 and 72 respectively, then the mass number and atomic number for $A_{4}$ :

172 and 69

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

174 and 70

No worries! We‘ve got your back. Try BYJU‘S free classes today!

176 and 69

No worries! We‘ve got your back. Try BYJU‘S free classes today!

176 and 70

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 172 and 69
As we know, mass and charge of
$α = 4$ and $+ 2$
$β = 0$ and $- 1$
$γ = 0$ and $0$

So $A α ⟶ A_{1} β ⟶ A_{2} {α ⟶ A}_{3} {γ ⟶ A}_{4}$
m 180 176 176 172 172
e 72 70 71 69 69

So mass and charge of $A_{4}$ is 172 & 69.

Suggest Corrections

Similar questions

Q. A radioactive nucleus undergoes a series of decay according to the scheme

A α \to A_{1}^{-} A_{2} α \to A_{3} γ \to A_{4}

.
If the mass number and atomic number of

A

are

180

and

72

respectively. The mass numbers of

A_{4}

is (integer only)

Q. A radioactive nucleus undergoes a series of decay according to the scheme

α, β, α, γ

.
If the mass number and atomic number of '

A

' before emissions are

180

and

72

respectively, then what are these numbers after the emissions?

Q. A radioactive nucleus undergoes a series of decays according to the sequence

A β \to A_{1} α \to A_{2} α \to A_{3}

If the mass number and atomic number of

A_{3}

are

172

and

69

respectively, then the mass number and atomic number of A is

Q. In a series of radioactive decays, if a nucleus of mass number

180

and atomic number

72

decays into another nucleus of mass number

172

and atomic number

69

, then the number of

α

and

β

particles released respectively are

Q. A hypothetical radioactive nucleus decays according to the following series

_{72} A^{180} α \to A_{1} β^{-} - \to A_{2} α \to A_{3} Υ \to A_{4}

If the mass number and atomic number of A are respectively

180

and

72

. then the atomic number and mass number of A will respectively be:

Join BYJU'S Learning Program

A radioactive nucleus undergoes a series of decay according to the scheme: Aa⟶A1β⟶A2α⟶A3γ⟶A4If the mass number and atomic number of `A' are 180 and 72 respectively, then the mass number and atomic number for A4:

The correct option is B 172 and 69As we know, mass and charge of α=4 and +2 β=0 and −1 γ=0 and 0So Aα⟶A1β⟶A2α⟶A3γ⟶A4m 180 176 176 172 172e 72 70 71 69 69So mass and charge of A4 is 172 & 69.

A radioactive nucleus undergoes a series of decay according to the scheme:
$A a ⟶ A_{1} β ⟶ A_{2} {α ⟶ A}_{3} {γ ⟶ A}_{4}$

If the mass number and atomic number of `A' are 180 and 72 respectively, then the mass number and atomic number for $A_{4}$ :

The correct option is B 172 and 69
As we know, mass and charge of
$α = 4$ and $+ 2$
$β = 0$ and $- 1$
$γ = 0$ and $0$

So $A α ⟶ A_{1} β ⟶ A_{2} {α ⟶ A}_{3} {γ ⟶ A}_{4}$
m 180 176 176 172 172
e 72 70 71 69 69

So mass and charge of $A_{4}$ is 172 & 69.