A radioactive nucleus undergoes a series of decay according to the scheme A -A1 - A2 - A3 - A4-If the mass number and atomic number of A are 180 and 72 respectively- The mass numbers of A4 is integer only

Given, _72A^180 The given process can be expressed as follows, A α→A_1 β^ → A_2 α→ A_3 γ→ A_4 _72A^180 α→ _70A_1^176 β^ → _71A_2^176 α→ _69A_3^172 nbsp; ...

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Standard X

Physics

Radioactivity

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Question

A radioactive nucleus undergoes a series of decay according to the scheme $A α \to A_{1}^{-} A_{2} α \to A_{3} γ \to A_{4}$ .
If the mass number and atomic number of $A$ are $180$ and $72$ respectively. The mass numbers of $A_{4}$ is (integer only)

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Solution

Given, $_{72} A^{180}$

The given process can be expressed as follows,

$A α \to A_{1}^{-} A_{2} α \to A_{3} γ \to A_{4}$

$_{72} A^{180} α \to_{70} A_{1}^{176}^{-}_{71} A_{2}^{176} α \to_{69} A_{3}^{172} {γ \to}_{69} A_{4}^{172}$

Thus, the mass number of $A_{4}$ is $172$

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A radioactive nucleus undergoes a series of decay according to the scheme Aα→A1 β−→A2 α→A3 γ→A4. If the mass number and atomic number of A are 180 and 72 respectively. The mass numbers of A4 is (integer only)

Given, 72A180 The given process can be expressed as follows, Aα→A1β−→A2α→A3γ→A4 72A180 α→ 70A1761 β−→ 71A1762 α→ 69A1723 γ→69A1724 Thus, the mass number of A4 is 172

A radioactive nucleus undergoes a series of decay according to the scheme $A α \to A_{1}^{-} A_{2} α \to A_{3} γ \to A_{4}$ .
If the mass number and atomic number of $A$ are $180$ and $72$ respectively. The mass numbers of $A_{4}$ is (integer only)

Given, $_{72} A^{180}$

The given process can be expressed as follows,

$A α \to A_{1}^{-} A_{2} α \to A_{3} γ \to A_{4}$

$_{72} A^{180} α \to_{70} A_{1}^{176}^{-}_{71} A_{2}^{176} α \to_{69} A_{3}^{172} {γ \to}_{69} A_{4}^{172}$

Thus, the mass number of $A_{4}$ is $172$