Question

A radioactive nuclide is produced at a constant rate of $\alpha$ per second. It's decay constant is $\lambda$. If $N_0$ be the no. of nuclei at time $t=0$, then max. no. of nuclei possible are:

• A. $N_0$
• B. $\alpha /\lambda$
• C. $N_0+\frac{\alpha }{\lambda }$
• D. $\frac{\lambda }{\sigma }+N_{0}s$

Answer 1

Answer: (B)

$\alpha /\lambda$

$\frac{dt}{dt}=\alpha -\lambda N,Formax.noofnuclei\frac{dN}{dt}=0\alpha =\lambda N\Rightarrow N=\alpha /\lambda$