A radioactive sample undergoes decay as per the following graph. At time $t = 0$ , the number of undecayed nuclie is $N_{0}$ . Calculate the number of nuclei left after $1 h$

N_{0} / e^{8}

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N_{0} / e^{10}

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N_{0} / e^{12}

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N_{0} / e^{14}

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Solution

The correct option is C $N_{0} / e^{12}$
From the graph the half life of the sample is $t_{1 / 2} = 3.47$ min
Now, $N = N_{0} e^{- λ t} = N_{0} e^{- (0.693 / 3.47)} 60 = N_{0} e^{- 12}$

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A radioactive sample undergoes decay as per the following graph. At time t=0, the number of undecayed nuclie is N0. Calculate the number of nuclei left after 1h

The correct option is C N0/e12From the graph the half life of the sample is t1/2=3.47 min Now, N=N0e−λt=N0e−(0.693/3.47)60=N0e−12

A radioactive sample undergoes decay as per the following graph. At time $t = 0$ , the number of undecayed nuclie is $N_{0}$ . Calculate the number of nuclei left after $1 h$

The correct option is C $N_{0} / e^{12}$
From the graph the half life of the sample is $t_{1 / 2} = 3.47$ min
Now, $N = N_{0} e^{- λ t} = N_{0} e^{- (0.693 / 3.47)} 60 = N_{0} e^{- 12}$