A radioactive substance is decaying with t1/2=30 days. On being separated into two fractions, one of the fractions, immediately after separation, decays with t1/2=2 days. The other fraction, immediately after separation would show:
A
constant activity
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
increasing activity
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
decay with t1/2=30 days
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
decay with t1/2=28 days
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B increasing activity From basic radioactivity, we know that separation of nuclei, giving one finite t1/2 would lead to another unstable (in this case) nuclei. So option B correct.