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Question

A rail road car is moving with a constant acceleration of 1 m/s2. A block of 5 kg is put on a horizontal rough floor in the car. At time t=0, velocity of the car is 5 m/s. Considering friction is sufficient and block is not slipping on the floor, the work done on the block by friction force (as observed from ground frame) during t=0 to t=2 sec will be (coefficient of friction is μs):
1019548_d623dacd79a140d18f0a70a53c736b8e.png

A
60J
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B
10J
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C
600μsJ
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D
None of these
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Solution

The correct option is A 60J
seudo force acts on the block placed on a car...
Fseudo=ma (a is accleration of a car)
Now since the block is not slipping therefore friction is sufficient to balance the suedo force....
ffriction=Fseudo=5N
During t=0 to t=2sec, displacement of car is
S=ut+.5at2
S=12m(a=1m/s2,u=5m/s,t=2)
Work done by friction
60J


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