There is no friction and car is moving on its track
By using the conservation of momentum we get
1).200×4=200×v1
v1=800200
v1=4m/s
When a body is thrown sideways then there will not be any change in the velocity of the car.
2)P=m1v1+m2v2
800=200×v1+20×2
v1=3.8m/s
As the body is thrown backward out of the car then the velocity of the car will be3.8m/s
3). 200×4=m1v1+m2v2
800=200×v1+20×(−4)
v1=4.4m/s