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Question

A railway track runs parallel to a road until a turn brings the road to railway crossing. A cyclist rides along the road everyday at a constant speed 20 km/hr. He normally meets a train that travels in same direction at the crossing. One day he was late by 25 minutes and met the train 10 km before the railway crossing. The speed of the train (in km/hr) is 30 N ,then N is

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Solution

tcycle=10 km20 km/ h=12 h=30 min
Δt=5 min=560 hr
Train running as per schedule
So Vtrain=10(560)=10×605=120 kmh1

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