A railway truck of mass $2 \times 10^{4} k g$ , travelling at $0.5 m s^{- 1}$ collides with another of half of it's mass moving in opposite direction with a velocity of $0.4 m s^{- 1}$ . If they stick together after the collision then their common velocity is:

0.2

^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.4

^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.6

^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.8

^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $0.2$ ms $^{- 1}$
Using momentum conservation,

$m_{1} u_{1} + m_{2} u_{2} = V (m_{1} + m_{2})$

$m_{1} = 2 \times 10^{4}$ kg $, m_{2} = 10^{4}$ kg $, u_{1} = 0.5$ ms $^{- 1}, u_{2} = - 0.4$ ms $^{- 1}, V = ?$

$\Rightarrow 20000 \times 0.5 + 10000 \times (- 0.4) = 30000 V$

$\Rightarrow V = \frac{20000 \times 0.5 - 10000 \times 0.4}{30000} = 0.2$ $m s^{- 1}$ .

Suggest Corrections

Similar questions

A 2 kg mass moving with a velocity of $10 m s^{- 1}$ collides with another 6 kg mass moving in opposite direction with a velocity of $20 m s^{- 1}$ . After the collision, they stick and move together. Find their common velocity and the momentum.

Q. A 2 kg mass moving with a velocity of

10 m s^{- 1}

collides with another 6 kg mass moving in opposite direction with a velocity of

20 m s^{- 1}

. After the collision, they stick and move together. Their common velocity is m/s and the momentum is kg m/s.

Q. A 2 kg mass moving with a velocity of

10 m s^{- 1}

collides with another 6 kg mass moving in opposite direction with a velocity of

20 m s^{- 1}

. After the collision, they stick and move together. Their common velocity is m/s and the momentum is kg m/s.

Q. A railway truck of mass 16,000 kg moving with a velocity of

5

^{- 1}

strikes another truck of mass 4,000 kg at rest. If they move together after impact, their common velocity is

Ball A of mass $5 k g$ travelling at $6 m s^{- 1}$ collides with another ball B of mass $2 k g$ travelling at $2 m s^{- 1}$ in the same direction. After collision, the velocity of ball A reduces to $2 m s^{- 1}$ . Calculate the velocity of ball B after the collision.

Join BYJU'S Learning Program

A railway truck of mass 2×104 kg, travelling at 0.5 ms−1 collides with another of half of it's mass moving in opposite direction with a velocity of 0.4 ms−1. If they stick together after the collision then their common velocity is:

The correct option is A 0.2 ms−1Using momentum conservation,m1u1+m2u2=V(m1+m2)m1=2×104kg,m2=104kg,u1=0.5ms−1,u2=−0.4ms−1,V=?⇒20000×0.5+10000×(−0.4)=30000V⇒V=20000×0.5−10000×0.430000=0.2 ms−1.

A railway truck of mass $2 \times 10^{4} k g$ , travelling at $0.5 m s^{- 1}$ collides with another of half of it's mass moving in opposite direction with a velocity of $0.4 m s^{- 1}$ . If they stick together after the collision then their common velocity is: