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Question

A rain drop starts falling from a height of 2 km. It falls with a continuously decreasing acceleration and attains its terminal
velocity at a height of 1 km. The ratio of the work done by the gravitational force in the first half to the that in the second
half to the drops journey is

A
1:1 and the time of fall of the drop in the two halves is a:1 (where a>1)
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B
1:1 and the time of fall of the drop in the two halves is a:1 (where a<1)
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C
a:1 (where a>1) and the time of fall of the drop in the two halves is 1:1
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D
a:1 (where a<1) and the time of fall of the drop in the two halves is 1:1
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Solution

The correct option is A 1:1 and the time of fall of the drop in the two halves is a:1 (where a>1)
Since the height of fall is 1km being very small compared to the radius of the earth we can assume to remain constant throughout (The work done mgx for x distance moved) is clearly same for both values of the rain drops journey. Since the drop attains speed V at the end of first half of journey average speed during half is V/2. The speed of the drop during second half is constant and equal to V through out. The time of fall of the drop during the first half is therefore greater than the corresponding time during second half. So, correct answer is 1:1 and the time of fall of the drop in the two halves is a:1 where a>1.

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