A random process has auto correlation function Rx- -Acos4-0- - where A and -0 are constants- If the average power of the process is given as Pavg- then the ratio Px-PavgA is equal to-

P_avg=R_x(0)=A ∴ P_avgA=1 ...

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Standard XII

Biology

Blackman's Law of Limiting Factor

A random proc...

Question

A random process has auto correlation function $R_{x} (τ) = A {cos}^{4} (ω_{0} τ),$ where A and $ω_{0}$ are constants. If the average power of the process is given as $P_{a v g},$ then the ratio $P_{x} = \frac{P_{a v g}}{A}$ is equal to,

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Solution

The correct option is C 1
$P_{a v g} = R_{x} (0) = A$

$∴ \frac{P_{a v g}}{A} = 1$

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A random process has auto correlation function Rx(τ)=Acos4(ω0τ), where A and ω0 are constants. If the average power of the process is given as Pavg, then the ratio Px=PavgA is equal to,

The correct option is C 1Pavg=Rx(0)=A ∴PavgA=1

A random process has auto correlation function $R_{x} (τ) = A {cos}^{4} (ω_{0} τ),$ where A and $ω_{0}$ are constants. If the average power of the process is given as $P_{a v g},$ then the ratio $P_{x} = \frac{P_{a v g}}{A}$ is equal to,

The correct option is C 1
$P_{a v g} = R_{x} (0) = A$

$∴ \frac{P_{a v g}}{A} = 1$