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Question

A random variable has the following probability distribution:
X = xi : 1 2 3 4
P (X = xi) : k 2k 3k 4k
Write the value of P (X ≥ 3).

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Solution

We know that the sum of probabilities in a probability distribution is always 1.

∴ P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4) = 1

k+2k+3k+4k=110k=1k=110Now, PX3=PX=3+PX=4=310+410=710

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