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Byju's Answer
Standard XII
Mathematics
Conditional Probability
A random vari...
Question
A random variable has the following probability distribution:
X = x
i
:
1
2
3
4
P (X = x
i
) :
k
2k
3k
4k
Write the value of P (X ≥ 3).
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Solution
We know that the sum of probabilities in a probability distribution is always 1.
∴ P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4) = 1
⇒
k
+
2
k
+
3
k
+
4
k
=
1
⇒
10
k
=
1
⇒
k
=
1
10
Now
,
P
X
≥
3
=
P
X
=
3
+
P
X
=
4
=
3
10
+
4
10
=
7
10
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