You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Standard Deviation about Mean for Continuous Frequency Distributions

A random vari...

Question

A random variable X has following probability distribution.
$X = x$ $1$ $2$ $3$ $4$ $5$ $6$
$P (X = x)$ K $3 K$ $5 K$ $7 K$ $8 K$ K
Then $P (2 \leq x < 5) =$ _______.

\frac{3}{5}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{7}{25}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{23}{25}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{24}{25}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{3}{5}$
$s i n c e \sum P (x) = 1 k + 3 k + 5 k + 7 k + 8 k + k = 1 k = 1 / 25 P (2 \leq x < 5) = P (2) + P (3) + P (4) = 3 k + 5 k + 7 k = 15 k = 15 / 25 = 3 / 5$

Suggest Corrections

Similar questions

Q. A random variable

x

has the following probability distribution:

$x$	$0$	$1$	$2$	$3$	$4$	$5$	$6$
$P (X = x)$	$k$	$3 k$	$5 k$	$7 k$	$9 k$	$11 k$	$13 k$

Find

^{'} k^{'}

Q. A random variable

X

has the following probability distribution:

$X = x$	$0$	$1$	$2$	$3$	$4$	$5$	$6$
$P (X = x)$	$k$	$3 k$	$5 k$	$7 k$	$9 k$	$11 k$	$13 k$

(a) Find

k

(b) Find

P (0 < X < 4)

X

Q. A random variable

X

has the following probability distribution:

$X$	$0$	$1$	$2$	$3$	$4$	$5$	$6$	$7$
$P (X)$	$0$	$k$	$2 k$	$2 k$	$3 k$	$k^{2}$	$2 k^{2}$	$7 k^{2} + k$

Determine
(i)

k

(ii)

P (X < 3)

(iii)

P (X > 6)

(iv)

P (0 < X < 3)

Q. The probability distribution of a discrete random variable

X

is:

$X = x$	$1$	$2$	$3$	$4$	$5$
$P (X = x)$	$k$	$2 k$	$3 k$	$4 k$	$5 k$

Find

P (X \leq 4)

Q. A random variable

X

has the following probability mass function.

$x$	$0$	$1$	$2$	$3$	$4$	$5$	$6$
$P (X = x)$	$k$	$3 k$	$5 k$	$7 k$	$9 k$	$11 k$	$13 k$

(a) Find

k

.
(b) Evaluate

P (X < 4), P (X

\geq

5)

and

P (3 < X

\leq

6)

.
(c) What is the smallest value of

x

for which

P (X

\leq

x) >

\frac{1}{2}

Join BYJU'S Learning Program

A random variable X has following probability distribution.X=x123456P(X=x)K3K5K7K8KKThen P(2≤x<5)= _______.

The correct option is B 35since∑P(x)=1k+3k+5k+7k+8k+k=1k=1/25P(2≤x<5)=P(2)+P(3)+P(4)=3k+5k+7k=15k=15/25=3/5

A random variable X has following probability distribution.
$X = x$ $1$ $2$ $3$ $4$ $5$ $6$
$P (X = x)$ K $3 K$ $5 K$ $7 K$ $8 K$ K
Then $P (2 \leq x < 5) =$ _______.

The correct option is B $\frac{3}{5}$
$s i n c e \sum P (x) = 1 k + 3 k + 5 k + 7 k + 8 k + k = 1 k = 1 / 25 P (2 \leq x < 5) = P (2) + P (3) + P (4) = 3 k + 5 k + 7 k = 15 k = 15 / 25 = 3 / 5$