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Byju's Answer
Standard XII
Mathematics
Intersection of Sets
A random vari...
Question
A random variable
X
has the following probability distribution:
X
=
x
0
1
2
3
4
5
6
P
(
X
=
x
)
k
3
k
5
k
7
k
9
k
11
k
13
k
(a) Find
k
(b) Find
P
(
0
<
X
<
4
)
(c) Obtain cumulative distribution function (c.d.f) of
X
.
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Solution
(a)
K
+
3
K
+
5
K
+
7
K
+
9
K
+
11
K
+
13
K
=
1
∴
49
K
=
1
∴
K
=
1
49
(b)
P
(
0
<
x
<
4
)
=
P
(
1
)
+
P
(
2
)
+
P
(
3
)
3
49
+
10
49
+
21
49
=
34
49
(c) C.D.F
=
(
2
x
+
1
)
K
,
0
≤
x
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