MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Probability Distribution

A random vari...

Question

A random variable X has the following probability distribution.
X 0 1 2 3 4 5 6
P(X) K 3K 5K 7K 9K 11K 13K
Find K, $P (X \geq 2)$

Open in App

Solution

Sum of probabilities is $1$
$⟹ k + 3 k + 5 k + 7 k + 9 k + 11 k + 13 k = 49 k = 1 k = \frac{1}{49} p (X \geq 2) = 5 k + 7 k + 9 k + 11 k + 13 k = 45 k = \frac{45}{49}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. A random variable X has the following probability distribution. X 0 1 2 3 4 5 6 7 P (X) 0 k 2 k 2 k 3 k k 2 2 k 2 7 k 2 + k Determine (i) k (ii) P (X < 3) (iii) P (X > 6) (iv) P (0 < X < 3)

Q. The random variable x has a probability distribution

P (x)

of the following form where

k

is some number:

P (x) = ⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩ \begin{matrix} k & i f x = 0 2 k & i f x = 1 3 k & i f x = 2 0 & o t h e r w i s e \end{matrix}

Determine the value of

k

P (X \leq 2) .

Q. A random variable

X

has the following probability distribution:

$X$	$0$	$1$	$2$	$3$	$4$
$P (X)$	$0.1$	$k$	$2 k$	$2 k$	$k$

k

P (X \geq 2)

Q. A random variable X has the following probability distribution:

Values of X :	−2	−1	0	1	2	3
P (X) :	0.1	k	0.2	2k	0.3	k

Find the value of k.

Q. The random variable X has probability distribution P(X) of the following form, where k is some number: (a) Determine the value of k . (b) Find P(X < 2), P(X ≥ 2), P(X ≥ 2).

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Probability Distribution

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Probability Distribution

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon