Question

A rational number lying between $\sqrt{2}\mathrm{and}\sqrt{3}$ is
(a) $\frac{\left(\sqrt{2}+\sqrt{3}\right)}{2}$
(b) $\sqrt{6}$
(c) 1.6
(d) 1.9

Answer 1

Since, $\frac{\left(\sqrt{2}+\sqrt{3}\right)}{2}$ and $\sqrt{6}$ are irrational numbers,

And, $\sqrt{2}=1.414\mathrm{and}\sqrt{3}=1.732$

So, the rational number lying between $\sqrt{2}\mathrm{and}\sqrt{3}$ is 1.6 .

Hence, the correct option is (c).