A rational number lying between -2 and -3 is a -2-3-2 b -6 c 1-6 d 1-9

Since, (√(2)+√(3))/2 and √(6) are irrational numbers, And, √(2) =1.414 and √(3) = 1.732 So, the rational number lying between √(2) =1.414 and √(3) is 1.6 . Henc ...

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Standard IX

Mathematics

Rational Numbers

A rational nu...

Question

A rational number lying between $\sqrt{2}$ and $\sqrt{3}$ is

(a) $\frac{(\sqrt{2} + \sqrt{3})}{2}$ (b) $\sqrt{6}$ (c) 1.6 (d) 1.9

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Solution

Since, $\frac{(\sqrt{2} + \sqrt{3})}{2}$ and $\sqrt{6}$ are irrational numbers,

And, $\sqrt{2}$ =1.414 and $\sqrt{3}$ = 1.732

So, the rational number lying between $\sqrt{2}$ =1.414 and $\sqrt{3}$ is 1.6 .

Hence, the correct option is (c).

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Similar questions

Q. A rational number lying between

\sqrt{2} and \sqrt{3}

is
(a)

\frac{(\sqrt{2} + \sqrt{3})}{2}

(b)

\sqrt{6}

Q. A rational number lying between

\sqrt{2}

and

\sqrt{3}

is :

Two rational numbers between $\frac{2}{3}$ and $\frac{5}{3}$ are

(a) $\frac{1}{6}$ and $\frac{2}{6}$
(b) $\frac{1}{2}$ and $\frac{2}{1}$
(c) $\frac{5}{6}$ and $\frac{7}{6}$
(d) $\frac{2}{3}$ and $\frac{4}{3}$

Q. Question 8
A rational number between

\sqrt{2}

and

\sqrt{3}

is

A)

\frac{\sqrt{2} + \sqrt{3}}{2}

\frac{\sqrt{2} . \sqrt{3}}{2}

C) 1.5
D) 1.8

The rational number which is not lying between $\frac{5}{16}$ and $\frac{1}{2}$ is
$(a) \frac{3}{8}$

$(b) \frac{7}{16}$

$(c) \frac{1}{4}$

$(d) \frac{13}{32}$

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A rational number lying between √2 and √3 is (a) (√2+√3)2 (b) √6 (c) 1.6 (d) 1.9

Since, (√2+√3)2 and √6 are irrational numbers, And, √2 =1.414 and √3 = 1.732 So, the rational number lying between √2 =1.414 and √3 is 1.6 . Hence, the correct option is (c).

A rational number lying between $\sqrt{2}$ and $\sqrt{3}$ is

(a) $\frac{(\sqrt{2} + \sqrt{3})}{2}$ (b) $\sqrt{6}$ (c) 1.6 (d) 1.9

Since, $\frac{(\sqrt{2} + \sqrt{3})}{2}$ and $\sqrt{6}$ are irrational numbers,

And, $\sqrt{2}$ =1.414 and $\sqrt{3}$ = 1.732

So, the rational number lying between $\sqrt{2}$ =1.414 and $\sqrt{3}$ is 1.6 .

Hence, the correct option is (c).