Question

A ray, emerging from a point on the object, passing through the center of curvature C strikes the mirror normally i.e. at ${90}^o$. Then, the angle of incidence is equal to

• A. $0^o$
• B. ${45}^o$
• C. ${90}^o$
• D. ${180}^o$

Answer 1

The correct option is C ${90}^o$

A ray, emerging from a point on the object, passing through the centre of curvature C strikes the mirror normally i.e. at ${90}^o$. Then, the angle of incidence is equal to ${90}^o$ for forward ray and ${180}^o$ for retraced ray.