A ray gets successively reflection from two mirrors inclined at an angle of $40_{0}$ . If the angle of incidence on the first mirror is $40_{0}$ then the net deviation of this ray is

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Solution

Given,

Angle of the incidence is $40^{0}$

So according to the formula of the net deviation:

$360^{0} - 2 θ$

$= 360^{0} - 2 \times 40$

$= 280^{0}$

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A ray gets successively reflection from two mirrors inclined at an angle of 400. If the angle of incidence on the first mirror is 400 then the net deviation of this ray is

Given,Angle of the incidence is 400So according to the formula of the net deviation:3600−2θ=3600−2×40=2800

A ray gets successively reflection from two mirrors inclined at an angle of $40_{0}$ . If the angle of incidence on the first mirror is $40_{0}$ then the net deviation of this ray is

Given,

Angle of the incidence is $40^{0}$

So according to the formula of the net deviation:

$360^{0} - 2 θ$

$= 360^{0} - 2 \times 40$

$= 280^{0}$