A ray gets successively reflection from two mirrors inclined at an angle of $40^{o}$ . If the angle of incidence on the first mirror is $30^{o}$ then the net deviation of this ray after two reflections :

40^{o}

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280^{o}

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180^{o}

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240^{o}

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Solution

The correct option is B $280^{o}$
Angle of deviation in case of double reflection is given as
$δ = 360 ° - 2 θ = 360 ° - 2 (40 °) = 360 ° - 80 ° = 280 °$

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Similar questions

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A ray gets successively reflection from two mirrors inclined at an angle of 40o. If the angle of incidence on the first mirror is 30o then the net deviation of this ray after two reflections :

The correct option is B 280oAngle of deviation in case of double reflection is given as δ=360°−2θ=360°−2(40°)=360°−80°=280°

A ray gets successively reflection from two mirrors inclined at an angle of $40^{o}$ . If the angle of incidence on the first mirror is $30^{o}$ then the net deviation of this ray after two reflections :

The correct option is B $280^{o}$
Angle of deviation in case of double reflection is given as
$δ = 360 ° - 2 θ = 360 ° - 2 (40 °) = 360 ° - 80 ° = 280 °$