Question

A ray is incident at an angle ${38}^o$ on a mirror. The angle between normal and reflected ray is _________.

• A. ${38}^o$
• B. ${52}^o$
• C. ${90}^o$
• D. ${76}^o$

Answer 1

The correct option is B ${52}^o$

The angle between the reflected ray and incident ray is measured w.r.t the normal.

The angle between the incident ray and reflected ray=$\frac{1}{2}\left(\angle i+\angle r\right)$

It is given that the angle of incidence is${38}^{{}^{\circ }}$with the surface of the normal.

So,the angle of the reflection will be ${90}^{\circ }-{38}^{{}^{\circ }}={52}^{{}^{\circ }}$with the surface of normal.