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A ray OA is incident upon a smooth surface POQ. It is reflected back along OB, a normal ON is drawn perpendicular to the surface at O (the point of incidence) and the value of AOP is
60. Find the value of x.


A

30

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B

40

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C

50

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D

60

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Solution

The correct option is A

30


Given, AOP=60

As ON is perpendicular to POQ
AOP+AON=90

AON=9060
AON=30

By laws of reflection,
Angle of incidence = Angle of reflection
AON=BON=x
Thus,
Angle of reflection x=30


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