240

You visited us 240 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Physics

Laws of Reflection

A ray OA is i...

Question

A ray OA is incident upon a smooth surface POQ. It is reflected back along OB, a normal ON is drawn perpendicular to the surface at O (the point of incidence) and the value of $∠ A O P$ is $60^{\circ}$ . Find the value of x.

$30^{\circ}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$40^{\circ}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$50^{\circ}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$60^{\circ}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$30^{\circ}$

Given, $∠ A O P = 60^{\circ}$

As ON is perpendicular to POQ
$∠ A O P + ∠ A O N = 90^{\circ}$

$⟹ ∠ A O N = 90^{\circ} - 60^{\circ}$
$∠ A O N = 30^{\circ}$

By laws of reflection,
Angle of incidence = Angle of reflection
$⟹ ∠ A O N = ∠ B O N = x$
Thus,
$A n g l e o f r e f l e c t i o n x = 30^{\circ}$

Suggest Corrections

Similar questions

Q. A ray incident at a point at an angle of incidence of

60^{o}

enters a glass sphere of refractive index

\sqrt{3}

and is reflected and refracted at the farther surface of the sphere. The angle between the reflected and refracted rays at this surface is:

A ray OA is incident upon a smooth surface POQ. It is reflected back along OB, a normal ON is drawn perpendicular to the surface at O (the point of incidence) and the value of $∠ A O P$ is $60^{\circ}$ . Find the value of x.

A ray

OA

is incident upon a smooth surface

POQ

. It is reflected back along

OB

, a normal

ON

is drawn perpendicular to the surface at

O

(the point of incidence) and the value of

∠ AOP

60^{\circ}

. Find the value of

x

in degrees.

A ray OA is incident upon a smooth surface POQ. It is reflected back along OB. A normal ON is drawn perpendicular to the surface at O (the point of incidence). The value of $∠ A O P$ is $60^{\circ}$ . Find the value of the angle of reflection.

In the given figure, a ray OA is incident upon a smooth surface POQ. It is reflected back along OB. A normal ON is drawn perpendicular to the surface at O (the point of incidence). The value of $∠ A O P$ is $60^{\circ}$ . Find the value of the angle of reflection.

Join BYJU'S Learning Program

A ray OA is incident upon a smooth surface POQ. It is reflected back along OB, a normal ON is drawn perpendicular to the surface at O (the point of incidence) and the value of ∠AOP is 60∘. Find the value of x.

The correct option is A 30∘ Given, ∠AOP=60∘ As ON is perpendicular to POQ ∠AOP+∠AON=90∘ ⟹∠AON=90∘−60∘​ ∠AON=30∘ By laws of reflection, Angle of incidence = Angle of reflection ⟹ ∠AON=∠BON=x Thus, Angle of reflection x=30∘

A ray OA is incident upon a smooth surface POQ. It is reflected back along OB, a normal ON is drawn perpendicular to the surface at O (the point of incidence) and the value of $∠ A O P$ is $60^{\circ}$ . Find the value of x.