Question

A ray of light along $x+\sqrt{3}y=\sqrt{3}$ gets reflected upon reaching the $x$-axis, an equation of the reflected ray is

• A. $\sqrt{3y}=x+\sqrt{3}$
• B. $y=\sqrt{3x}-\sqrt{3}$
• C. $\sqrt{3y}=x-1$
• D. $y=x+\sqrt{3}$

Answer 1

Answer: (A)

$\sqrt{3y}=x+\sqrt{3}$

The given equation is $x+\sqrt{3}y=\sqrt{3}$

$\sqrt{3}y=\sqrt{3}-x$

To find the reflected ray, we replace f(x) by f(-x), we get

$=\sqrt{3}y=\sqrt{3}-(-x)$

$=\sqrt{3}y=\sqrt{3}+x$

Therefore option(D) is correct.