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Question

A ray of light along x+3y=3 gets reflected upon reaching x-axis. Equation of the reflected rays is

A
3 y=x3
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B
y=3x3
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C
3 y=x1
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D
y=x+3
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Solution

The correct option is B 3 y=x3
x+3y=3
y=13x+1
Hence the line makes an angle of 300 with respect to x axis.
Hence the reflected line will make a +300 angle with the x axis.
Thus the equation of the line will be of the form
y=x3+c ...(i) where c is a constant.
Now the reflected line and the original line meet where the original line cuts the x axis.
The point is x=3
Hence substituting the point (3,0) in equation i gives us
0=1+c
Or
c=1
Hence the equation of the reflected line will be
y=x31
3yx+3=0

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