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Question

A ray of light coming from the point P(2,3) is reflected at a point Q on the x- axis and then passes through the point R(4,5). The equation of PQ is

A
x+y=5
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B
3xy=3
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C
4x+y=11
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D
2x+y=7
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Solution

The correct option is C 4x+y=11
Let Q be the point of intersection of incident ray and xaxis, image of R w.r.t x axis , R(4,5)


P,Q,R are collinear
So,equation of PR or PQ by Point-slope form is y3=4(x2)
4x+y=11

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