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Question

A ray of light emerging from the point source placed at P(1,2) is reflected at a point Q on the y-axis and then passes through the point (6,9). Then

A
Q(0,3)
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B
image of P in yaxis is (1,2)
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C
equation of incident ray is x+y=3
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D
equation of reflected ray is y=x+3
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Solution

The correct options are
A Q(0,3)
B image of P in yaxis is (1,2)
C equation of incident ray is x+y=3
D equation of reflected ray is y=x+3
Let P be the reflection of P in y-axis

P=(1,2)

So, the equation of the line PQ(reflected ray)

y2=926+1(x+1)

y=x+3

y-axis intersection with the line at Q

Q=(0,3)
So, the equation of incident ray PQ will be x+y=3

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