A ray of light enters a glass slab ABDC as shown in Fig- 4-64 and strikes at the centre O of the circular part AC of the slab- The critical angle of glass is 42- Complete the path of the ray till it emerges out from the slab- Mark the angles in the diagram whereever necessary- -3 marks-

[1.5 marks] The angle of refraction will be 90^∘ because the ray is incident on the glass at its critical angle. [1.5 marks] ...

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Standard X

Physics

Total Internal Reflection

A ray of ligh...

Question

A ray of light enters a glass slab ABDC as shown in Fig. 4.64 and strikes at the centre O of the circular part AC of the slab. The critical angle of glass is $42^{\circ}$ . Complete the path of the ray till it emerges out from the slab. Mark the angles in the diagram whereever necessary. [3 marks]

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Solution

$[1.5 marks]$

The angle of refraction will be $90^{\circ}$ because the ray is incident on the glass at its critical angle.
$[1.5 marks]$

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A ray of light enters a glass slab ABDC as shown in Fig. 4.64 and strikes at the centre O of the circular part AC of the slab. The critical angle of glass is 42∘. Complete the path of the ray till it emerges out from the slab. Mark the angles in the diagram whereever necessary. [3 marks]

[1.5 marks] The angle of refraction will be 90∘ because the ray is incident on the glass at its critical angle. [1.5 marks]

A ray of light enters a glass slab ABDC as shown in Fig. 4.64 and strikes at the centre O of the circular part AC of the slab. The critical angle of glass is $42^{\circ}$ . Complete the path of the ray till it emerges out from the slab. Mark the angles in the diagram whereever necessary. [3 marks]

$[1.5 marks]$

The angle of refraction will be $90^{\circ}$ because the ray is incident on the glass at its critical angle.
$[1.5 marks]$