A ray of light enters a spherical drop of water of refractive index $μ$ as shown in fig. An expression of the angle between incident ray and emergent ray (angle of deviation) as shown in fig. is :

0^{\circ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

ϕ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

α - ϕ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

π - 4 α + 2 ϕ

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B $π - 4 α + 2 ϕ$
$α = (ϕ - α) + θ$
$δ = π - 2 θ = π - 4 α + 2 ϕ$ .

Suggest Corrections

Similar questions

Q. A ray of light enters a spherical drop of water of refractive index

μ

as shown in the figure. The angle

ϕ

for which minimum deviation is produced will be given by :

A ray of light enters a spherical drop of water of refractive index

n = \sqrt{3}

as shown in figure. If

ϕ = 60^{\circ}

, then

Q. A ray of light enters a spherical drop of water of refractive index

μ

as shown in fig. Select the correct statement(s).

Q. A ray of light falls on the surface of spherical glass paperweight making an angle

α

with the normal and is refracted in the medium at an angle

β

. The angle of deviation of the emergent ray from the incident ray is

Two parallel light rays are incident at one surface of a prism of refractive index 1.5 as shown in figure. The angle between the emergent rays is nearly

Join BYJU'S Learning Program

A ray of light enters a spherical drop of water of refractive index μ as shown in fig. An expression of the angle between incident ray and emergent ray (angle of deviation) as shown in fig. is :

The correct option is B π−4α+2ϕα=(ϕ−α)+θδ=π−2θ=π−4α+2ϕ.

A ray of light enters a spherical drop of water of refractive index $μ$ as shown in fig. An expression of the angle between incident ray and emergent ray (angle of deviation) as shown in fig. is :

The correct option is B $π - 4 α + 2 ϕ$
$α = (ϕ - α) + θ$
$δ = π - 2 θ = π - 4 α + 2 ϕ$ .