A ray of light falling normally on a plane mirror, then angle of reflection will be:

90^{\circ}

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180^{\circ}

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0^{\circ}

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45^{\circ}

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Solution

The correct option is D $0^{\circ}$
For normal incidence on a plane mirror, the angle of reflection will be zero.

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If a ray of light falls along the normal of a plane mirror, then the light ray will reflect back at angle of?

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