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Question

A ray of light falls on a transparent glass slab with refractive index (relative to air) of 1.62. The angle of incidence for which the reflected and refracted rays are mutually perpendicular is

A
tan1(1.62)
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B
sin1(1.62)
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C
cos1(1.62)
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D
None of these
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Solution

The correct option is C tan1(1.62)


From law of reflection:-

r=i

And from figure:-

R+90o+r=180o

R=90or

R=90oi

Now from Snell's Law:-
sinisinR=μ

sinisin(90oi)=μ

sinicosi=μ

tani=μi=tan1μ

i=tan1(1.62)

Answer-(A)


833621_691702_ans_a5efac79bbed4b909b1d9be9d975c072.jpg

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