A ray of light falls on the surface of a spherical glass paper weight making an angle α with the normal and is refracted in the medium at an angle β. The angle of deviation of the emergent ray from the direction of the incident ray is
A
(α−β)
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B
2(α−β)
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C
(α−β)2
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D
(α+β)
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Solution
The correct option is B2(α−β) From figure it is clear that ΔOBC is an isosceles triangle ,
Hence ∠OCB=β and emergent angle is α
Also sum of two in terior angles = exterior angle ∴δ=(α−β)+(α−β)=2(α−β)