A ray of light from a denser medium strikes a rarer medium at an angle of incidence i as shown in the figure. The reflected and refracted rays make an angle of 90∘ with each other. The angles of reflection and refraction are r and r′. The critical angle is
sin−1(tan r)
From figure, i = r and r' = 90∘−r
Now, n=sin r′sin r=sin(90∘−r)sin r
⇒n=cos rsin r=1tan r
We know that, n=1sin C
where C = critical angle
∴1sin C=1tan r
⇒C=sin−1(tan r)