A ray of light from a denser medium strikes a rarer medium at angle of incidence i as shown in the figure. The reflected and refracted rays make an angle of 90∘ with each other. The angles of reflection and refraction are r and r′ respectively. The critical angle is
sin−1(tanr)
i=r [Law of reflection]
r′=90∘−r [Given]
Now, refractive index, n=sinr′sinr=sin(90∘−r)sin r [Snell's Law]
⇒n=cosrsinr=1tanr
We know that, n=1sinC where C= critical angle
∴1sinC=1tanr
⇒C=sin−1(tanr)