A ray of light incident at a small angle on a small angle glass prism- The deviation produced by the prism for a ray in air is - When the prism is immersed in water of refractive index 4 3- then the angle of deviation of the ray would be refractive index of glass - 3 2

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Physics

Angle of Deviation in Prism

A ray of ligh...

Question

A ray of light incident at a small angle on a small angle glass prism. The deviation produced by the prism for a ray in air is $δ$ . When the prism is immersed in water of refractive index $\frac{4}{3}$ , then the angle of deviation of the ray would be (refractive index of glass $= \frac{3}{2}$ )

\frac{δ}{2}

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δ

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\frac{δ}{8}

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\frac{δ}{4}

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Solution

The correct option is C $δ$
$δ=A(μ−1)δ= deviation A= prism angle μ= refractive index of prism so Deviation doesn't depend on the refractive index of surroundings. so angle of deviation is same in both cases. Deviation =δ option B .is correct$

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Similar questions

Q. The light ray is incident at an angle of

60^{\circ}

on a prism of angle

45^{\circ}

. When the light ray falls on the other surface at

90^{\circ}

, the refractive index of the material of prism

μ

and the angle of deviation

δ

are given by

Q. (a) A ray 'PQ' of light is incident on the face AB of a glass prism ABC (as shown in the figure) and emerges out of the face AC. Trace the path of the ray. Show that

∠ i + ∠ e = ∠ A + ∠ δ

. When

δ

and e denote the angle of deviation and angle of emergence respectively.

Plot a graph showing the variation of the angle of deviation as a function of angle of incidence. State the condition under which

δ

is minimum.

(b) Find out the relation between the refractive index (

μ

) of the glass prism and

∠ A

for the case when the angle of prism (A) is equal to the angle of minimum deviation

(δ_{m})

. Hence obtain the value of the refractive index for angle of prism

A = 60^{\circ}

Q. Assertion :Angle of deviation depends on the angle of prism. Reason: For thin prism

δ = (μ - 1) A

where

δ =

angle of deviation,

μ =

refractive index,

A =

angle of prism

A ray of light enters a spherical drop of water of refractive index

n = \sqrt{3}

as shown in figure. If

ϕ = 60^{\circ}

, then

Q. In an experiment for determination of refractive index of glass of a prism by

i - δ

, plot , it was found that a ray incident at angle

35^{0}

, suffers a deviation of

40^{0}

and that it emerges at angle

79^{0}

. In which of the following is closest to the maximum possible value of the refractive index ?

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A ray of light incident at a small angle on a small angle glass prism. The deviation produced by the prism for a ray in air is δ. When the prism is immersed in water of refractive index 43, then the angle of deviation of the ray would be (refractive index of glass =32)

The correct option is C δδ=A(μ−1)δ= deviation A= prism angle μ= refractive index of prism so Deviation doesn't depend on the refractive index of surroundings. so angle of deviation is same in both cases. Deviation =δ option B .is correct

A ray of light incident at a small angle on a small angle glass prism. The deviation produced by the prism for a ray in air is $δ$ . When the prism is immersed in water of refractive index $\frac{4}{3}$ , then the angle of deviation of the ray would be (refractive index of glass $= \frac{3}{2}$ )

The correct option is C $δ$
$δ=A(μ−1)δ= deviation A= prism angle μ= refractive index of prism so Deviation doesn't depend on the refractive index of surroundings. so angle of deviation is same in both cases. Deviation =δ option B .is correct$