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Question

A ray of light incident on the first mirror parallel to the second and is reflected from the second mirror parallel to first mirror. The angle between two mirrors is

A
30
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B
60
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C
75
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D
90
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Solution

Step 1: Given

Let M₁ and M₂ are the mirrors.

The incident ray is parallel to mirror M₂,

The reflected ray is parallel to mirror M₁,

Let the angle between the mirrors is(BDC) = θ.

Draw a normal for the reflections from the mirrors.

Step 2: Formula used

Angle of incidence= Angle of reflection

Step 3: Finding the angle between the mirrors

Then ∠ M₁BA=θ and ∠ ECM₂=θ(corresponding angles).

Hence, M₁BA= DBC=θ(linear pair).

Similarly, ECM₂= DCB=θ.

DBC +DCB +BDC =180o

θ+ θ+ θ =180o

3θ =180o

θ =60o

Hence, the angle between the mirrors is 60o.


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