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Question

A ray of light is incident along a line which meets another line, 7xy+1=0, at the point (0,1). The ray is then reflected from this point along the line, y+2x=1. Then the equation of the line of incidence of the ray of light is :

A
41x25y+25=0
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B
41x38y+38=0
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C
41x+38y38=0
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D
41x+25y25=0
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Solution

The correct option is B 41x38y+38=0
From the question we can draw the following figure

Now,from laws of reflection, we know that
angle between normal and incident ray=angle between normal and reflected ray.
Let slope of incident ray be m,
slope of normal=17 and slope of reflected ray=2
m+171m7=17+21+27m=4138
So, the equation of incident ray
y1=4138(x0)41x38y+38=0

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