Question

A ray of light is incident at ${60}^{\circ }$ on glass-air interface. Then the total deviation of the ray is ___ degrees.

${\mu }_g$ = $\sqrt{2}$, ${\mu }_a$ = 1

Answer 1

Since critical angle is ${45}^{\circ }$. All angles above ${45}^{\circ }$ will undergo Total Internal Reflection.

$Deviation=\pi -2i$
$Deviation={180}^{\circ }-(2\times {60}^{\circ })={60}^{\circ }$