Question

A ray of light is incident at ${60}^{\circ }$ on glass-air interface. What will happen to the ray?

${\mu }_g$ = $\sqrt{2}$, ${\mu }_a$ = 1

• A. 90°
• B. 30°
• C. 60°
• D. 180°

Answer 1

Answer: (A), (B)

The correct options are
A

90°

B

30°

Since critical angle is ${45}^0$. All angles above ${45}^0$ will undergo Total Internal Reflection.

$\Pi -2i=Deviation={180}^{\circ }-2\times {60}^{\circ }={60}^{\circ }$