A ray of light is incident at an angle i from denser to rare medium. The reflected and the refracted rays are mutually perpendicular. The angle of reflection and the angle of refraction are respectively r and r’, then the critical angle will be
A
sin−1(sinr)
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B
sin−1(tanr′)
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C
sin−1(tani)
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D
tan−1(sini)
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Solution
The correct option is Csin−1(tani) DμR=sinisinr′⇒RμD=sinr′sini=1sinC⇒sinC=sinisin(90−r)=sinicosr=sinicosi(as∠i=∠r)⇒sinC=tani⇒C=sin−1(tani)