A ray of light is incident at an angle of incidence ‘i’ on one face of a prism of angle A (assumed to be small) and emerge normally from the opposite face. If the refractive index of the prism is μ, the angle of incidence i, is nearly equal to:
A
μA
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B
μA2
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C
Aμ
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D
A2μ
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Solution
The correct option is AμA For a thin prism [Assumed to be small] i+e=A+δ(i) for minimum deviation since its emerges normally, l = 0 δ=(μ–1)A(ii)∴i+A+δUsing(i)and(ii)i=A+(μ−1)Ai=A+μA–Ai=μA