Question

A ray of light is incident at polarizing angle such that its deviation is ${24}^o$, then angle of incidence is :

• A. ${24}^o$
• B. ${57}^o$
• C. ${66}^o$
• D. ${90}^o$

Answer 1

The correct option is B ${57}^o$

Here,

Incident polarising angle, $i_p=r+\delta$

$i_p=r+24$ .....$\left(i\right)$

Moreover, $i_p+r={90}^o$ .....$\left(ii\right)$

From Eqs. $\left(i\right)$ and $\left(ii\right)$, we get

$i_p+(i_p-24)={90}^o$

$\Rightarrow i_p={57}^o$