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Question

A ray of light is incident at the glass–water interface at an angle i, it emerges finally parallel to the surface of water, then the value of μg would be 


Your Answer
A
(43).sin(i)
Correct Answer
B
1sin(i)
Your Answer
C
43
Your Answer
D
1

Solution

The correct option is B 1sin(i)
Given :μw=43

Since the ray finally emerges
parallel to the water surface.  
r must be the critical angle.

sin(r)=sin(90)μwsin(r)=1μwsin(r)=34  

At the water-glass interface
μg.sin(i)=μw.sin(r)μg=μw×sin(r)sin(i)    =43×34sin(i)    =1sin(i)

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