A ray of light is incident from air to water- If the angle of incidence is 60- find the angle of refraction- Given the refractive index of water is 4-3-

From the Snell's law, sin i/sin r=μ ⇒sin 60^∘/sin r =4/3 ∴ r = 40.5^∘ ...

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Standard X

Physics

Refraction

A ray of ligh...

Question

A ray of light is incident from air to water. If the angle of incidence is $60^{\circ}$ , find the angle of refraction. Given the refractive index of water is $\frac{4}{3}$ .

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Solution

From the Snell's law, $\frac{s i n i}{s i n r} = μ$
$\Rightarrow \frac{s i n 60^{\circ}}{s i n r} = \frac{4}{3}$
$∴ r = {40.5}^{\circ}$

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A ray of light is incident from air to water. If the angle of incidence is 60∘, find the angle of refraction. Given the refractive index of water is 43.

From the Snell's law, sin isin r=μ ⇒sin 60∘sin r=43 ∴r=40.5∘

A ray of light is incident from air to water. If the angle of incidence is $60^{\circ}$ , find the angle of refraction. Given the refractive index of water is $\frac{4}{3}$ .

From the Snell's law, $\frac{s i n i}{s i n r} = μ$
$\Rightarrow \frac{s i n 60^{\circ}}{s i n r} = \frac{4}{3}$
$∴ r = {40.5}^{\circ}$