A ray of light is incident normally on one of the faces of a prism of apex angle 30∘ and refractive index √2. The angle of deviation of the ray is _________ degrees.
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Solution
Using Snell's law for the refraction at AC, we get μsini=(1)sinr√2sin30∘=sinr. sinr=1√3r=45∘ Angle of deviation =45∘−30∘=15∘